设减少x棵黄瓜秧苗,使得黄瓜收获最多,由题意得:
y=(100-x)(
x
1 ×0.1+2)
=-0.1x2+8x+200,
=-0.1(x-40)2+360,
∴当x=40棵时,y最多=360千克.
故答案为:40,360.